Question 486047
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You cannot find <i>the</i> equation of a line since there are many ways to describe the set of ordered pairs that comprise any given line.  You can, however, determine <i>an</i> equation whose solution set is a set of ordered pairs that comprise a line with the given characteristics.  Use the point-slope form.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the given slope.


It looks from the last line of your question that the slope-intercept form (*[tex \Large y\ =\ mx\ +\ b]) is the desired form of the answer.


So distribute the *[tex \Large m] across *[tex \Large x\ -\ x_1], add *[tex \Large y_1] to both sides, and combine *[tex \Large -mx_1\ +\ y_1\ =\ b].
  

John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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