Question 486000
{{{(5 + 1/3i) -(1/2 -1/2i)}}}


={{{5 + 1/3i - 1/2 + 1/2i}}}


={{{(5 - 1/2) + (1/2i+ 1/3i)}}} 


={{{4(1/2) + (1*3i)/(2i*3i)+ (1*2i)/(3i*2i)}}} 


= {{{9/2 + (3i+ 2i)/(6i^2)}}} 


= {{{9/2 + (5i)/(6(-1))}}} 


={{{9/2 + (5i)/(-6)}}} 


={{{9/2-(5i)/6}}}