Question 485962

e<sup>x<sup>2</sup>+5x+6</sup> = 1

e is merely the base of natural logarithms.  You don't even need
to know its value which is approximately 2.718.

Since you know that any number to the 0 power is 1

rewrite the 1 on the right side as e<sup>0</sup>

e<sup>x²+5x+6</sup> = e<sup>0</sup>

Now you can simply set the exponents of e equal to each other:

x² + 5x + 6 = 0

And you can easily solve that by factoring.

Answers: -2 and -3

Edwin</pre>