Question 485670
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The argument is valid because the contrapositive of a conditional proposition always has the same truth value as the original proposition:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ p\ \Rightarrow\ {q}\ \Leftrightarrow\ \neg{q}\ \Rightarrow \neg{p}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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