<PRE><B>Question 485387</B>
&lt;pre&gt;
Here are all the cards
&lt;font color = &quot;red&quot;&gt;

(A&amp;#9829;) 2&amp;#9829; 3&amp;#9829; 4&amp;#9829; 5&amp;#9829; 6&amp;#9829; 7&amp;#9829; 8&amp;#9829; 9&amp;#9829; 10&amp;#9829; J&amp;#9829; (Q&amp;#9829;) K&amp;#9829; 
(A&amp;#9830;) 2&amp;#9830; 3&amp;#9830; 4&amp;#9830; 5&amp;#9830; 6&amp;#9830; 7&amp;#9830; 8&amp;#9830; 9&amp;#9830; 10&amp;#9830; J&amp;#9830; (Q&amp;#9830;) K&amp;#9830;&lt;/font&gt;
(A&amp;#9824;) 2&amp;#9824; 3&amp;#9824; 4&amp;#9824; 5&amp;#9824; 6&amp;#9824; 7&amp;#9824; 8&amp;#9824; 9&amp;#9824; 10&amp;#9824; J&amp;#9824; (Q&amp;#9824;) K&amp;#9824; 
(A&amp;#9827;) 2&amp;#9827; 3&amp;#9827; 4&amp;#9827; 5&amp;#9827; 6&amp;#9827; 7&amp;#9827; 8&amp;#9827; 9&amp;#9827; 10&amp;#9827; J&amp;#9827; (Q&amp;#9827;) K&amp;#9827; 

We want the probability of getting one of the 8 that are
in parentheses out of the total 52.  So the probability is
8 out of 52 or 8/52 which reduces to 2/13.


Edwin&lt;pre&gt;&lt;b&gt;
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