Question 485156
i have five digits.
a, b, c, d, e
: 
 my tens digit is 2 less than my hundreds digit.
d = c - 2
:
 my thousands digit is 3 more than my hundreds digit.
b = c + 3
:
 my ten thousands digit is equal to my hundreds digit.
a = c
;
 my tens digit is 3.
d = 3
:
 the sum of my digits is 25. 
a + b + c + d + e = 25
Replace the above with the given equations
c + (c+3) + c + 3 + e = 25
3c + 6 + e = 25
3c + e = 25 - 6
3c + e = 19
from the 2nd equation, d = c-2, and we are given that d=3, therefore
c - 2 = 3
c = 5
3(5) + e = 19
e = 19 - 15
e = 4
:
Using the above information we find that:
a = 5
b = 8
c = 5
d = 3
e = 4
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tot 25

what number am i.. : 58534