Question 484659
How do you graph x squared + 10x + y squared + 20y -19 = 0
***
x^2+10x+y^2+20y-19=0
completing the square
(x^2+10x+25)+(y^2+20y+100)=19+25+100=144
(x+5)^2+(y+10)^2=144
This is an equation of a circle of the standard form: (x-h)^2+(y-k)^2=r^2, with (h,k) being the (x,y) coordinates of the center.
For given equation:
Center: (-5,-10)
Radius: √144=12
see graph below as a visual check on the answers:
..
y=±(144-(x+5)^2)^.5-10
{{{ graph( 300, 300, -20, 20, -20, 20,(144-(x+5)^2)^.5-10,-(144-(x+5)^2)^.5-10) }}}