Question 484911
a {{{function}}} associates a {{{single}}} {{{output}}} to each {{{input}}}; in other words, for any value of {{{x}}} you plug in to the {{{first}}} equation, you can find a single value for {{{y}}} 

son your answer is a.  y = −3x − 5 

However, in the second, third, and fourth equation , for every value of {{{x}}} that you plug in there are {{{two}}} possible values of {{{y}}} that will work.


{{{y^2 = -3x}}}

{{{y^2 =-3(-3)=9}}}

{{{y =sqrt(9)}}}
 
{{{y }}}=+-{{{3}}}

 so, if {{{x}}} is {{{-3}}}, {{{y}}} can be either {{{3}}} or {{{-3}}}