Question 484877


{{{5x-2y=10}}}...this is equation in standard form and we will rewrite it in {{{slope-intercept}}} form {{{y=mx+-b}}} (where {{{m}}} is a {{{slope}}} and {{{b}}} is {{{y-intercept}}})like this:

{{{5x-10=2y}}}

{{{(5/2)x-10/2=y}}}

{{{y=(5/2)x-5}}}

so, a {{{slope}}} is: {{{m=5/2}}}

{{{y-intercept}}} is: {{{b=-5}}}

 how to find the x-intercept...set {{{y=0}}}


{{{5x-10=2*0}}}

{{{5x-10=0}}}


{{{5x=10}}}

{{{x=10/5}}}

{{{x=2}}}


check it on a graph:

{{{ graph( 500, 500, -10, 10, -10, 10, (5/2)x-5) }}}