Question 484880
x-intercept {{{y=0}}}, {{{5x=10}}} => {{{x=2}}}, point (2,0)
y- intercept {{{x=0}}}, {{{-2y=10}}} => {{{y=-5}}}, point (0,-5)
slope-intercept form of the equation is {{{y=mx+b}}}, where {{{m}}} is a slope
{{{5x-2y=10}}}
{{{-2y=-5x+10}}}divide by -2
{{{y=2.5x-5}}}, then the slope is {{{m=2.5}}}