Question 484510
Assume that you have surveyed 1068 randomly selected adult Americans and 279 have indicated that they would vote for Andrew Mason if he were to run for Congress. Construct a 95% confidence interval for the percentage of voters who would vote for Mason. State the margin of error.
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phat = 279/1068 = 0.2612
ME = 1.96*sqrt[0.26*0.74/1068] = 0.0263
95% CI : 0.2612-0.0263 < p < 0.2612+0.0263
 
After computing, my margin of error is = .0263 and my CI is = .2349 < P < .2875 
is this correct?.
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You are correct.
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Cheers,
Stan H.