<PRE><B>Question 484372</B>
{{{(y^2-10y+25)/(y^2+2y-35)}}} Start with the given equation.



{{{((y-5)(y-5))/(y^2+2y-35)}}} Factor the numerator.



{{{((y-5)(y-5))/((y-5)(y+7))}}} Factor the denominator.



{{{(highlight((y-5))(y-5))/(highlight((y-5))(y+7))}}} Highlight the common terms.



{{{(cross((y-5))(y-5))/(cross((y-5))(y+7))}}} Cancel out the common terms.



{{{(y-5)/(y+7)}}} Simplify.



So {{{(y^2-10y+25)/(y^2+2y-35)=(y-5)/(y+7)}}}



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