Question 49887
    I am not coming up with the correct answer for this. I am leaving something out. Can someone help me showing the step by step process?
    Solve by using the quadratic formula:

    X2 = 2X + 4
X^2-2X-4=0.............STANDARD FORMULA
FOR ROOTS OF.........AX^2+BX+C=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (2 +- sqrt( 2^2-4*1*(-4) ))/(2*1) }}} 
{{{x = (2 +- sqrt( 4+16 ))/(2) }}} 
{{{x = (2 +- sqrt( 20 ))/(2) }}} 
{{{x = (2 +- 2*sqrt( 5))/(2) }}} 
{{{x = (1 +- sqrt( 5 )) }}}