Question 484195
Rectangle 1 has a length of 1 divide by x-1 and a width of x-2
Rectangle 2 has a length of 2 divided by x+1 and a width of x

Rectangle 1 Area ={{{(1/(x-1))*(x-2)}}}

Rectangle II Area ={{{(2/(x+1))*x}}}

Add Them
{{{(1/(x-1))*(x-2)}}}+{{{(2/(x+1))*x}}}


{{{((x-2)/(x-1))+(2x/(x+1))}}}

LCD = (x+1)(x-1)

{{{(((x+1)(x-2))+(2x(x-1)))/((x+1)(x-1))}}}

{{{(x^2-x-2+2x^2-2x)/((x+1)(x-1))}}}

{{{(3x^2-3x-2)/((x^2-1))}}}