<PRE><B>Question 484137</B>
x1		y1	x2	y2				
4		0	3.8	2				
								
slope m =		(y2-y1)/(x2-x1)						
(	2	-	0	)/(	3.8	-	4	) 
(	2	/	-0.2	)  				
m=		-10      						 


x1		y1	x2	y2				
3		9	7	15				
								
slope m =		(y2-y1)/(x2-x1)						
(	15	-	9	)/(	7	-	3	) 
(	6	/	4	)  				
m=		3/ 2						 
								
Plug value of  the slope  and point(	3	,	9	) in	
Y 	=	m	x 	+	b			
9.00	=	9/2	+	b				
b=	9	-	9/2					
b=	9/ 2							
So the equation  will be								
Y 	=	3/2	x 	+	9/2	

The slope of line perpendicular to the above line will be -2/3		
</PRE>