Question 483794
{{{ 2x^2+2y^2=5 }}}

{{{ 2y^2=5-2x^2 }}}

{{{ 2y^2/2=(5-2x^2)/2 }}}

{{{y^2=(5-2x^2)/2 }}}
<pre>
Use the principle of square roots:

{{{y="" +- sqrt((5-2x^2)/2) }}}

Rationalizing the denominator:

{{{y="" +- sqrt(expr((5-2x^2)/2)*expr(2/2)) }}}


{{{y="" +- sqrt((2(5-2x^2))/4) }}}

{{{y="" +- sqrt((10-4x^2)/4) }}}

{{{y="" +- sqrt(10-4x^2)/2 }}}

Edwin</pre>