Question 483728
{{{(3+2i)^2}}}


{{{3^2+6*2i+(2i)^2}}}

{{{9+12i+4(i)^2}}}....recall that {{{(i)^2=-1}}}

{{{9+12i+4(-1)}}}

{{{9+12i-4}}}

{{{5+12i}}}

and

{{{i^3-i^2}}}

{{{i^2*i-i^2}}}


{{{-1*i-(-1)}}}

{{{-i+1}}}