Question 483723

given:

The perimeter of a rectangular field is {{{P=366 yd}}}. 

 the width of the field is {{{highlight(W=86yd)}}}


{{{P=2(L+W)}}}

{{{P/2=L+W}}}


{{{L=P/2-W}}}


{{{L=366yd/2-86yd}}}


{{{L=183yd-86yd}}}


{{{highlight(L=97yd)}}}