Question 481978


Since one of the legs of the trapezoid is 5 cm, then the h (height) = 4, since a 3-4-5 right triangle would be formed by a segment of the longer base, the height, and one of the legs.


Formula for the area of an isosceles trapezoid = {{{(h*(b[1] + b[2]))/2}}}, with bases being {{{b[1]}}} and {{{b[2]}}} and height "h"


Since h (h) height = 4 cm, and bases, {{{b[1]}}} and {{{b[2]}}} being 6 and 12 cm, we get:


Area = {{{4*(6 + 12)/(2)}}} ------ {{{(4 * 18)/2}}} = {{{72/2}}} = {{{highlight_green(36cm^3)}}}