Question 482872
Again, another dice problem. As I indicated in the answer to one of your other problems, there are 36 possible outcomes on the roll of a pair of fair dice. These outcomes are:
.
1,1
1,2
1,3
1,4
1,5
1,6 
2,1
2,2
2,3
2,4
2,5
2,6 
3,1
3,2
3,3
3,4 
3,5 
3,6 
4,1
4,2
4,3 
4,4 
4,5 
4,6 
5,1
5,2 
5,3
5,4 
5,5 
5,6 
6,1 
6,2 
6,3 
6,4 
6,5 
6,6 
.
Out of the 36 possible outcomes, how many of the dice rolls total 6 or 9.  Count them up. You should find there are 9 of these "winners" beginning with 1,5 and ending with 6,3.  So the probability of winning on the first roll by rolling a 6 or a 9 is the number of winners (9 of them) divided by the total number of possible outcomes (36). 9 divided by 36 reduces to 1 divided by 4 which has a decimal equivalent of 0.25 (or 25%). You have a one in four chance of winning on the first roll. This suggests that in the long run on every 4 rolls you are likely to be a winner for one of those rolls.
.
Good luck. Just keep working at it and eventually it will start to make sense.
.