Question 6207
{{{sqrt(40)+sqrt(10)+sqrt(2)/5}}}
First get rid of the denominator by multiplying everything by 5:
{{{5*sqrt(40)+5*sqrt(10)+sqrt(2)}}}
The key to simplifying radicals is to factor what is inside the radical
{{{5*sqrt(2*2*2*5)+5*sqrt(2*5)+sqrt(2)}}}
then pull out groups of numbers according to the index on the radical - if there is no index, it is by twos.  In this case, we can only pull out a set of two "2"'s from the first radical sign.  When you pull out the group represent it in front of the radical by one of it's members

example:

{{{sqrt(3*3*3)=3*sqrt(3)}}}

so your problem becomes:
{{{5*2*sqrt(2*5)+5*sqrt(2*5)+sqrt(2)}}}
then add anything that has the same radical:
{{{10*sqrt(10)+5*sqrt(10)+sqrt(2)}}}
{{{15*sqrt(10)+sqrt(2)}}}