Question 482013
We will use the distance formula.
{{{sqrt((x2 -x1)^2 + (y2 - y1)^2 )}}} = {{{sqrt((0-2)^2 + (3 - 6)^2)}}} = {{{sqrt(13)}}}.
{{{sqrt((x2 -x1)^2 + (y2 - y1)^2 )}}} = {{{sqrt((1+1)^2 + (3 - 0)^2)}}} = {{{sqrt(13)}}}.
The two segments are equal, they are congruent.
Cleomenius.