Question 49727
  
    {{{x^2/((x-2)(x-3))  =  (2/(x-2))+(6/(x-2)(x-3))}}}
  
    {{{x^2/((x-2)(x-3))}}} = {{{(2(x-3)+6)/((x-2)(x-3))}}}
  
    As both the denominators are same,
    {{{x^2 = 2x-6+6}}}.  So, {{{x^2 = 2x}}}
  
    {{{x^2-2x = 0}}}.   {{{x(x-2) = 0}}}
 
    So either x or (x-2) = 0.
  
    Solution Set = {0, 2} Answer.