Question 483468


{{{sqrt(16x^4)}}}...first replace {{{16}}} with {{{4^2}}} and {{{x^4}}} with {{{(x^2)^2 }}}

={{{sqrt(4^2*(x^2)^2)}}}


={{{sqrt((4x^2)^2)}}}...cancel square root and power of two


={{{4x^2}}}