<PRE><B>Question 483467</B>
Find the equation of the line satisfying the given conditions, giving it in slope-intercept form if possible: 
Through (-4,1), parallel to x+3y=5
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Slope of the given line = ?
y = (-1/3)x + (5/3)
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slope = -1/3
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Any line parallel to the given line must have slope = -1/3
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Equation Form: 
y = mx + b
Solve for &quot;b&quot;:
1 = (-1/3)(-4) + b
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1 = (4/3) + b
b = -1/3
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Equation:
y = (-1/3)x - (1/3)
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Cheers,
Stan H.</PRE>