Question 483256
2	x	+	3	y  	=	12				
Find the slope of this line 										
										
3	y  	=	-2	x	+	12				
Divide by 	3									
	y  	=	- 2/3	x	+	4				
Compare this equation with y=mx+b										
slope m =	-2/3									
										
The slope of a line perpendicular to the above line will be the negative reciprocal	3/2
m1*m2=-1										
The slope of the required line will be 	3/2		
										
m=	3/2	,point	(	-4	,	6	)			
Find b by plugging the values of m & the point in										
y=mx+b										
6	=	-6.00	+	b						
b=	12									
m=	1 1/2									
The required equation is y =3/ 2x+12      			
m.ananth@hotmail.ca