Question 483178
Let x+1 and x+3 are two integer
3(x+1)+2(x+3)=39
3x+3+2x+6=39
5x+9=39
5x=39-9
5x=30
x=30/5
x=6

First odd integer = x+1=6+1=7
Second odd integer = x+3=6+3=9

7 and 9 are two consecutive odd integers