Question 483144
(y^2-25)/y ÷ (y-5)/(y+9)
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Invert the denominator and multiply to get:
(y^2-25)/y * (y+9)/(y-5)
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Factor:
[(y-5)(y+5)/y] *[(y+9)/(y-5)]
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Cancel the common (y-5) factor:
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= [(y+5)(y+9)]/y
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Cheers,
Stan H.
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