Question 483077
Iam not in understanding of the substitution method can someone please help? 
4x+6y=16
6x +y =3
**
Solve for y in the second equation
y=3-6x
sub 3-6x for y in first equation
4x+6(3-6x)=16
4x+18-36x=16
-32x=-2
x=2/32=1/16