Question 483059
One way to do this is to notice that {{{4=2^2}}} and {{{8=2^3}}}


So {{{4^4=(2^2)^4=2^(2*4)=2^8}}}


and {{{8^2=(2^3)^2=2^(3*2)=2^6}}}



In short, {{{4^4=2^8}}} and {{{8^2=2^6}}}




So {{{((4^4)/(8^2))^3=((2^8)/(2^6))^3}}}



Now, let's simplify the inner expression {{{(2^8)/(2^6)}}}



{{{(2^8)/(2^6)=2^(8-6)=2^2}}}



So this means that {{{((4^4)/(8^2))^3=(2^2)^3=2^(2*3)=2^6=64}}}



So in the end, {{{((4^4)/(8^2))^3=64}}}