Question 482737
Hi, I'm trying to do my precalc honors summer work, and I'm completely stuck on how to solve G(x)=x^3-8; I know it seems simple, but its although as soon as I get out of school for the summer, I completely forget how to do anything slightly complicated. Could you please explain to me how to create a table with enough points so that I can graph it by hand? Also, is there a vertex formula? It seems like there would be a vertex with this type of graph. I think the shape of it should be similar to that of an "S" because it is x^3, am I correct? 
-------------
G(x) = x^3-8
---
Form is "difference of cubes"
G(x) = (x-2)(x^2+4x+4)
----
Graph: Looks like x^3 but it is lower by 8
---------------------
{{{graph(400,400,-10,10,-20,20,x^3-8)}}}
====================
Cheers,
Stan H.
========