Question 482676
{{{x^2 -2x= 30}}}...take half of the coefficient (don't forget the sign!) of the {{{x-term}}} which is {{{half of {{{-2}}} is {{{-1}}},square it (which will be {{{(-1)^2=1}}}, and add this square to both sides of the equation

{{{x^2 -2x+1= 30+1}}}

{{{(x-1)^2=31}}}

{{{x-1}}}=+-{{{sqrt(31)}}}

{{{x-1}}}=+-{{{5.57}}}

solutions:

{{{x-1=5.57}}}  or {{{x-1=-5.57}}}


if {{{x-1=5.57}}}...->...{{{x=5.57+1}}}..->...{{{x=6.57}}}

or

if {{{x-1=-5.57}}}...->...{{{x=-5.57+1}}}..->...{{{x=-4.57}}}



check:

{{{(6.57)^2 -2(6.57)= 30}}}

{{{43.1649 -13.14= 30}}}

{{{30.0249= 30}}}

{{{30= 30}}}