Question 482429
the supplement of an angle is 16 less than three times the complement of the angle. Find the angle, its complement, and its supplement


Let the angle be A


Supplement of the angle = 180 - A


Complement of angle = 90 - A


Since the supplement of the angle is 16 less than three times the complement of the angle, we can say that:


180 - A = 3(90 - A) - 16


180 - A = 270 - 3A - 16


2A = 74


A, or angle = {{{74/2}}} = {{{highlight_green(37^o)}}}


Angle's complement = {{{90^o}}} - {{{37^o}}} = {{{highlight_green(53^o)}}} 


Angle's supplement = {{{180^o}}} - {{{37^o}}} = {{{highlight_green(143^o)}}}