Question 482443
let one side be x
second side = x+2
third side = x+4

x^2+(x+2)^2=(x+4)^2

x^2+x^2+4x+4=x^2+8x+16
x^2-4x-12=0
x^2-6x+2x-12=0
x(x-6)+2(x-6)=0
(x-6) (x+2)=0
x= 6 the length of smallest side.
6,8,10 are the three sides of the triangle.