Question 49767
Solve by using the quadratic formula. 
3x^2=11x+4
3X^2-11X-4=0.....COMPARING WITH ..AX^2+BX+C=0....
A=3........B=-11.....C=-4

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (11 +- sqrt( (-11)^2-4*3*(-4) ))/(2*3) }}}
{{{x = (11 +- sqrt( 121+48 ))/(6) }}}
{{{x = (11 +- sqrt( 169 ))/(6) }}}
X=(11+13)/6=4......OR
X=(11-13)/6=-2/6=-1/3