Question 49763
(4,3),(-4,-4)   [Given points]
m =(y2-y1)/(x2-x1)  [To find the slope, use the slope formula since two points are given]
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m =(-4-3)(-4-4)   [Plug-in the values]
m = -7/-8 = 7/8   [The slope of the line]
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Ax+By=C [General Form of the equation of the line]
(y-y1) = m(x-x1)   [Use the point-slope formula since you now have the slope and two points]
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(y-3) = (7/8)(x-4)  [Plug-in the values for the (m) and one of the points (4,3)]
y-3 = (7/8)x - (7/8)(4)  [Simplify]
y-3 = (7/8)x -7/2   [Isolate all of the variables on one side of the equation]
y-3+3 = (7/8)x-(7/2)+3
y = (7/8)x-(1/2)
y -(7/8)x = (7/8)x-(7/8)x -(1/2)
y -(7/8)x = -1/2  [Re-arrange the terms]
-7/8x + y = -1/2  [General Form of the equation of the line][Final answer]
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Check by plugging the values of the points back into the General Form]