Question 482047


{{{64u^3/112u^7}}}...simplify..divide both {{{64}}} and {{{112}}} by {{{16}}}

{{{cross(64)4u^3/cross(112)7u^7}}}


{{{4u^3/7u^7}}}....now apply exponent rule {{{a^m/a^n=a^m-n)


{{{4u^(3-7)}}}


{{{4u^(-4)}}}


{{{4/7u^4}}}