Question 482001
{{{ (-2)^5 + (-5)^2 }}}
You can always write these out the long way 
( if the numbers aren't very big ) and look at them
{{{ (-2)*(-2)*(-2)*(-2)*(-2) + (-5)*(-5) }}}
The main thing to notice is that there are an odd number of
(-2)'s and an even number of (-5)'s
Think of the (-2)'s grouped in pairs with one left over
(-2)*(-2) this is positive
(-2)*(-2) also positive
(-2) this is negative
So, you have (+) x (+) x (-) = (-)
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What if it was {{{ (-2)^67 }}} ?
You would pair these up the same way, so you'd have
a bunch of (+) x (+) x (+) . . . etc and one (-) left. that would
give you a minus result
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Back to your problem, then
{{{ (-2)^5 = -32 }}}
and
{{{ (-5)^2 = 25 }}}
{{{ -32 + 25 = -7 }}}
OK?