Question 481937
Recall that you cannot take the square root of a negative number. So this means that the radicand (the stuff inside the square root) MUST be zero or positive. 



So this means that {{{9x-1>=0}}}



{{{9x-1>=0}}} Start with the given inequality.



{{{9x>=0+1}}} Add {{{1}}} to both sides.



{{{9x>=1}}} Combine like terms on the right side.



{{{x>=(1)/(9)}}} Divide both sides by {{{9}}} to isolate {{{x}}}. 



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Answer:



So the domain is *[Tex \LARGE \left\{x\|x\ge\frac{1}{9}\right\}] (basically, x is any number greater than or equal to {{{1/9}}})



The domain in interval notation is <font size="8">[</font>*[Tex \LARGE \frac{1}{9},\infty]<font size="8">)</font>