Question 481936


{{{2x+4y=8}}} Start with the given equation.



{{{4y=8-2x}}} Subtract {{{2x}}} from both sides.



{{{4y=-2x+8}}} Rearrange the terms.



{{{y=(-2x+8)/(4)}}} Divide both sides by {{{4}}} to isolate y.



{{{y=((-2)/(4))x+(8)/(4)}}} Break up the fraction.



{{{y=-(1/2)x+2}}} Reduce.



So the equation {{{y=-(1/2)x+2}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-1/2}}} and the y-intercept is {{{b=2}}} note: the y-intercept is the point *[Tex \LARGE \left(0,2\right)]