Question 481928
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Construct a perpendicular to segment *[tex \Large ab] through *[tex \Large e].  This will be the altitude of the triangle in question.  Label the point of intersection of this perpendicular with segment *[tex \Large ab] as *[tex \Large x] and then label the intersection of *[tex \Large xe] and *[tex \Large cd] as *[tex \Large y].


Note that the measure of *[tex \Large df\ =\ 1] and *[tex \Large gc\ =\ 2] means that the measure of *[tex \Large fg\ =\ 3].


Since the measure of *[tex \Large fg] is one-half the measure of *[tex \Large ab], the measure of *[tex \Large ey] must be one-half the measure of *[tex \Large ex].  Further, the measure of *[tex \Large ey] must be equal to the measure of *[tex \Large bc] given as 3.  Therefore the altitude is 6.


Calculate the area of a triangle with base measure of 6 and altitude of 6.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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