Question 481674
1. Write an equation of the line containing the given point and parallel to the given line.
(-5,2); 4x=5y+7
4	x		-5	y  	=	7	
Find the slope of this line 							
make y the subject							
-5	y  	=	-4	x	+	7	
Divide by 	-5						
	y  	=	0.8	x		-1.4	
Compare this equation with y=mx+b							
slope m =	0.8			0.8			
The slope of a line parallel to the above line will be the same							
The slope of the required line will be 	0.8 => 4/5				
m=	4/5	,point	(	-5	,	2	)
Find b by plugging the values of m & the point in							
y=mx+b							
2	=	-4.00	+	b			
b=	6						
m=	4/5						
Plug value of  the slope  and b	in y = mx +b		
The required equation is y  	=	  4/ 5	x	+	6      

2.Write an equation of the line containing the given point and perpendicular to the given line.
(4,8); 9x+y=8
1	y  	=	-9	x	+	8			
Divide by 	1								
	y  	=	-9    	x	+	8			
Compare this equation with y=mx+b									
slope m =	-9.00								
									
The slope of a line perpendicular to the above line will be the negative reciprocal									
m1*m2=-1									
The slope of the required line will be 	1/9			0.11	=		
									
m=	 1/9	,point	(	4	,	8	)		
Find b by plugging the values of m & the point in									
y=mx+b									
8	=	0.44	+	b					
b=	68/9								
m=	 1/9								
The required equation is y=  (1/9)x+68/9		
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