Question 481557
The ages of a mother and daughter are 31 and 7 years respectively. 
In how many years will the mother's age be 3/2 times that of daughter
:
Let y = no. of years for this to be true
:
y + mothers age = {{{3/2}}}* y + daughter's age
the equation
y + 31 = {{{3/2}}}(y + 7)
Get rid of the denominator, multiply both sides by 2
2(y+31) = 3(y+7)
:
2y + 62 = 3y + 21
:
62 - 21 = 3y - 2y
:
y = 41 yrs for this to be true
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See if it works out
41 + 31 = {{{3/2}}}(41+7
72 = {{{3/2}}}(48)
72 = 3(24); confirms our solution
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Were these step understandable to you?