Question 481493
find the length  using distance formula

*[invoke Distance_Formula_for_Coordinate_Plane 2, 2, 8, 2]

so, major axis is  {{{6}}} long

*[invoke Distance_Formula_for_Coordinate_Plane 5, 3, 5, 1]

minor axis is  {{{2}}} long

 The length of the horizontal axis is 2a.

{{{2a=6}}}
{{{a=3}}}

    The length of the vertical axis is 2b.

{{{2b=2}}}
{{{b=1}}}

{{{x^2/3^2 +y^2/1^2 =1}}}

{{{x^2/9 +y^2 =1}}}


{{{ graph( 500, 500, -6, 5, -10, 10, sqrt(1-(x^2/9)), -sqrt(1-(x^2/9))) }}}