Question 481490
{{{ 36t^4 + 29t^2 - 7 = 0 }}}
Sub x for t^2
{{{36x^2 + 29x - 7 = 0}}}
*[invoke solve_quadratic_equation 36,29,-7]
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x = t^2 = 7/36
t = +sqrt(7)/6, -sqrt(7)/6
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x = t^2 = -1
t = -i, i