Question 481392
Mother’s age=m=31
Daughter’s age=d=7
 after y years mother and daughter will be
m+y= d+y
and the mother’s age be 3/2 times of daughter
(m+y)= (3/2) (d+y)
(m+y)= 3 (d+y)/2
2(m+y)=3(d+y)
2m+2y=3d+3y
2m-3d=3y-2y
y=2m-3d
y=2(31)-3(7)
y=62-21
y=41
In 41 years