Question 481377
Simplify each complex expression. Write your answer in standard form. 
7-5i over 2+3i 
and 
Provide the requested information for each parabola, ellipse, circle, or hyperbola. 
Identify the vertex and axis of symmetry of y=x^2-2x+5
**
(7-5i)/(2+3i)
multiply both numerator and denominator by (2-3i)
(7-5i)/(2+3i)*(2-3i)/(2-3i)
i^2=-1
(7-5i)(2-3i)/(2+3i)(2-3i)
(7-5i)(2-3i)=14-31i+15i^2=14-31i-15=-(1+31i)  (FOIL)
(2+3i)(2-3i)=4-9i^2=4+9=13 (difference of squares)
ans:
-(1+31i)/13
..
y=x^2-2x+5
complete the square
y=(x^2-2x+1)+5-1
y=(x-1)^2+4
This is an equation of a parabola of standard form: y=A(x-h)^2+k, (h,k) being the (x,y) coordinates of the vertex.
For given equation: vertex at (1,4) and axis of symmetry of x=1.