Question 481263
First factor out the common factor of 2
{{{2(33x^2-65x+28)=0}}}
Then find factors of (33*28) that add up to -65
The best way to do this is to break down the product into prime factors:
33*28 = 11*3*7*4
(11*3)+(7*4) = 33+28 = 61 
(11*7)+(3*4)= 77+12 = 89
(11*4)+(3*7) = 44+21 = 65
This means we can split -65x into -44x -21x
Use factor by grouping
{{{2(33x^2-44x-21x+28)=0}}}
{{{2(11x(3x-4)-7(3x-4))=0}}}
{{{2(3x-4)(11x-7)=0}}}
To find the roots, first divide out the 2 **notice, it has no effect on the roots**
Then solve for each factored expression separately 
{{{3x-4 = 0}}}
{{{3x=4}}}
{{{x = 4/3}}}
{{{11x-7 =0}}}
{{{11x=7}}}
{{{x = 7/11}}}
The two roots are x=4/3 and x=7/11