Question 481168
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Hi,
Find the equation of the circle that has the
Center (-4, 6) passes thru P ( 1, 2 )
Standard Form of an Equation of a Circle is {{{(x-h)^2 + (y-k)^2 = r^2}}}
where Pt(h,k) is the center and r is the radius
{{{(x+4)^2 + (y-6)^2 = r^2}}}
D = {{{sqrt ((x[1]-x[2])^2+(y[1]-y[2])^2))}}}
(-4, 6) 
( 1, 2 ) r ={{{ sqrt((-5)^2 + (4)^2) = sqrt(41)}}}  R^2 = 41
{{{(x+4)^2 + (y-6)^2 = 41}}}