Question 481153
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Hi,
x^3+8x^2+2x+16  Note: x = -8 is a root, thus(x+8) one factor
Applying synthetic division: (x^3+8x^2+2x+16)/(x+8) = x^2 + 2
-8	1	8	2	16
		-8	0	-16
	1	0	2	0
x^3+8x^2+2x+16 = (x+8)(x^2+2) = x^3 + 8x^2 + 2x + 16
                  F	First terms  x^3
                  O	Outside terms 2x
                  I	Inside term  8x^2
                  L	Last terms   16
2bc+4b-5c-10 = 2b(c + 2) - 5(c + 2 = (2b-5)(c+2)
                  F	First terms  2bc
                  O	Outside terms 4b
                  I	Inside term  -5c
                  L	Last terms   -10